x+(9-8-y)=10 y+y-(9-8-y)=2 x-y=xx-9.9x xy=11y-1 y=? x=? x+y-xy=?x+(9-8-y)=10y+y-(9-8-y)=2x-y=xx-9.9xxy=11y-1 y=?x=?x+y-xy=?

x+(9-8-y)=10 y+y-(9-8-y)=2 x-y=xx-9.9x xy=11y-1 y=? x=? x+y-xy=?x+(9-8-y)=10y+y-(9-8-y)=2x-y=xx-9.9xxy=11y-1 y=?x=?x+y-xy=? y+10x=x+y+9 10y+x=y+10x+27 若X/10=Y/8=Z/9则X+Y+Z/Y+Z=? X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 已知x²+y²+6x-2y+10=0,求8y分之9x²-y² + 4分之y-3x的值 已知x^2+y^2+6x-2y+10=0求8y/9x^2-y^2+4/y-3x 3x-2y=9 x-3y=2 x+y=5 x+2y=3 y=x 2x+y=8 x+y=5① x=3y+2① 9x-5y=1① 3x-2y=11① x-2y=y+1① 2x-y=7② x+3y=8② 6x-7y=2② 2x+3y=16② 2x-3y=10②3x+2y=y+1①2x-3y=10②D 9y=3x-(x-1),4(x+y)-(2x+4)=8y 已知y/x=9/10则(1-y/x)[x/(y-x)]? x+10y+9=10x+y怎么解 X+Y=9 8X+4Y=56 x+4y=9,x-4y=10 {10x+9y=493 x+y=52 x/10=y/8=z/9,求(x+y+z)/x+(x+y)?x/10=y/8=z/9,求(x+y+z)/(x+y)？不好意思 y+10x=x+y+9 10y+x=y+10x+27怎么做?六年级方程组！ 谁会解10x+y=6(x+y)+3 10y+x=4(x+y)+9 计算 [ ( x+y ) ( x-y ) ] ^ 9 ÷ ( y-x )^ 8 ÷ ( -x-y )^9