log2(x+1)=log4x解方程

log2(x+1)=log4x解方程 已知log2[log3(log4x)]=0,求x的值 已知Log2[Log3(Log4X)]=0,求X 解方程log4(3x+1)=log4x+log4(3+x) 解方程log4(3x+1)=log4x+log4(3+x).会的帮帮忙, log2(log3(log4x)=0 必修1数学：若log2[log3(log4X)]=0 解方程log4（3x+1）=log4x+log(3+x)最后是log4（3+x) 解方程log2(2-x)=log2(x-1)+1 已知函数y={log2 x-2}{log4x-1/2}2《《8不太好打请HI我 log2(x+1)+log2x=log2（6）解方程 解方程：log2(x+4)+log2(x-1)=1+log2(x+8) 方程log4X+X=7的解所在的区间是? 已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y 已知log2(log3(log4x))=log3(log4(log2y))=0,求x+y的值 已知:log2[log3(log4x)]=log3[log4（log2y)]=0 求x+y的值 log2[log3(log4x)]=log3[log4(log2y)]=0求x+y的值, log2[log3（log4x）]=0求解x值.麻烦写在纸上拍给我.