an=2n-1,bn=2*(1/3)^n,cn=anbn,求证c(n+1)注:C(n+1)
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an=2n-1,bn=2*(1/3)^n,cn=anbn,求证c(n+1)注:C(n+1)an=2n-1,bn=2*(1/3)^n,cn=anbn,求证c(n+1)注:C(n+1)an=2n-1,bn
an=2n-1,bn=2*(1/3)^n,cn=anbn,求证c(n+1)注:C(n+1)
an=2n-1,bn=2*(1/3)^n,cn=anbn,求证c(n+1)
注:C(n+1)
an=2n-1,bn=2*(1/3)^n,cn=anbn,求证c(n+1)注:C(n+1)
Cn=AnBn=(2n-1)*2*(1/3)^n
C(n+1)=[2(n+1)-1]*2*(1/3)^(n+1)=(2n+1)*2*(1/3)^(n+1)
C(n+1)
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