若xyz=1,求 x/(xy+x+1) +y/(yz+y+z) +z/(zx+z+1)越快越好~.
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若xyz=1,求x/(xy+x+1)+y/(yz+y+z)+z/(zx+z+1)越快越好~.若xyz=1,求x/(xy+x+1)+y/(yz+y+z)+z/(zx+z+1)越快越好~.若xyz=1,求
若xyz=1,求 x/(xy+x+1) +y/(yz+y+z) +z/(zx+z+1)越快越好~.
若xyz=1,求 x/(xy+x+1) +y/(yz+y+z) +z/(zx+z+1)
越快越好~.
若xyz=1,求 x/(xy+x+1) +y/(yz+y+z) +z/(zx+z+1)越快越好~.
如果是选择题 或者是判断题最好做
令x=y=z=1 然后代入 得1
这是最简单的办法
如果是大题就这样解
x/(xy+x+1) +y/(yz+y+z) +z/(zx+z+1)
=x/(xy+x+xyz)+y/(yz+y+1)+yz/(zyx+yz+y)
=1/(y+1+yz)+y/(yz+y+1)+yz/(y+1+yz)
=(1+y+yz)/(y+1+yz)
=1
多给点分,我把解答过程和讲解详细说给你
xyz=1
x/(xy+x+1) +y/(yz+y+z) +z/(zx+z+1)
=x/(xy+x+xyz)+y/(yz+y+1)+yz/(zyx+yz+y)
=1/(y+1+yz)+y/(yz+y+1)+yz/(y+1+yz)
=(1+y+yz)/(y+1+yz)
=1
抽象函数求偏导 u=f(x,xy,xyz),求u对xy及xz的偏导可设1=x,2=xy,3=xyz
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