化简(x²-2xy+y²-1)/x-y-1=?
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化简(x²-2xy+y²-1)/x-y-1=?化简(x²-2xy+y²-1)/x-y-1=?化简(x²-2xy+y²-1)/x-y-1=?(
化简(x²-2xy+y²-1)/x-y-1=?
化简(x²-2xy+y²-1)/x-y-1=?
化简(x²-2xy+y²-1)/x-y-1=?
(x2-2xy+y2-1)/(x-y-1)
=[(x-y)2-1]/(x-y-1)
=(x-y+1)*(x-y-1)/(x-y-1)
=x-y+1
={(x-y)²-1}/x-y-1
=(x-y-1)(x-y+1)/x-y-1
=x-y+1
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化简(x²-2xy+y²-1)/x-y-1=? 写上过程! 谢!
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