tan30°+sin60°-tan45°+cos0°=?
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tan30°+sin60°-tan45°+cos0°=?tan30°+sin60°-tan45°+cos0°=?tan30°+sin60°-tan45°+cos0°=?因为tan30°=√3/3,si
tan30°+sin60°-tan45°+cos0°=?
tan30°+sin60°-tan45°+cos0°=?
tan30°+sin60°-tan45°+cos0°=?
因为tan30°=√3/3,sin60°=√3/2,tan45°=1,cos0°=1
所以
tan30°+sin60°-tan45°+cos0°
=√3/3+√3/2-1+1
=2√3/6+3√3/6
=(2√3+3√3)/6
=5√3/6
tan45°-cos60°/sin60°×tan30°
tan30°+sin60°-tan45°+cos0°=?
3tan30°-tan45°+2sin60°
3tan30°+2sin60°-2tan45°
3tan30°-tan45°+2sin60°=?3tan30°-tan45°+2sin60°=?
(tan30°+tan45°)/(1-tan30°tan45°)-2sin60°-sin^2 40°-cos^2 40°
tan45°-cos60°/sin60°×tan30° tan45°-cos60°/先除以sin60°之后,得到的数在与tan30° 相乘
3tan30°×cos30°+tan45°+sin30°-sin60°求解要过程
tan30°sin60°+cos^30°-sin^45°tan45°
cos^245°+1/2tan45°-tan60°分之tan30°-sin60°
tan45°-cos60°等于多少?以及sin60°和tan30°等于多少?)
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