若tan(a+b)=3 tan(a-四分之派)=4/3则tan(b+四分之派)=

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若tan(a+b)=3tan(a-四分之派)=4/3则tan(b+四分之派)=若tan(a+b)=3tan(a-四分之派)=4/3则tan(b+四分之派)=若tan(a+b)=3tan(a-四分之派)

若tan(a+b)=3 tan(a-四分之派)=4/3则tan(b+四分之派)=
若tan(a+b)=3 tan(a-四分之派)=4/3则tan(b+四分之派)=

若tan(a+b)=3 tan(a-四分之派)=4/3则tan(b+四分之派)=
由于b+π/4 = (a+b) - (a-π/4)
所以tan(b+π/4) = tan[(a+b) - (a-π/4)] = [tan(a+b) - tan(a-π/4)] / [1 + tan(a+b) * tan(a-π/4)]
=(5/3) / (1 + 4) = 1/3

把式子全部拆开,算出tanA=1,tanB=1/2
带入可得答案为3