已知[sina(a-π/4)]/cos(π+2a)=根号2,则sina+cosa=?

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已知[sina(a-π/4)]/cos(π+2a)=根号2,则sina+cosa=?已知[sina(a-π/4)]/cos(π+2a)=根号2,则sina+cosa=?已知[sina(a-π/4)]/

已知[sina(a-π/4)]/cos(π+2a)=根号2,则sina+cosa=?
已知[sina(a-π/4)]/cos(π+2a)=根号2,则sina+cosa=?

已知[sina(a-π/4)]/cos(π+2a)=根号2,则sina+cosa=?
sin(a-π/4)]/cos(π+2a)=√2,
√2/2(sina-cosa) =-√2cos2a,
sina-cosa=-2(cos^2a-sin^2a),
sina-cosa=2(sina+cosa)(sina-cosa),
sina+cosa=1/2