若 cos(x+π/6)=-5/13 则 sin(π/6-2x)的值是
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若cos(x+π/6)=-5/13则sin(π/6-2x)的值是若cos(x+π/6)=-5/13则sin(π/6-2x)的值是若cos(x+π/6)=-5/13则sin(π/6-2x)的值是sin(
若 cos(x+π/6)=-5/13 则 sin(π/6-2x)的值是
若 cos(x+π/6)=-5/13 则 sin(π/6-2x)的值是
若 cos(x+π/6)=-5/13 则 sin(π/6-2x)的值是
sin(π/6-2x)
=cos(π/2-(π/6-2x))
=cos(π/3+2x)
=cos2(x+π/6)
=2cos^(2)(x+π/6)-1
=-119/169
sin(π/6-2x)=cos(x+π/6-2x-π/2)=cos(-π/3-2x)=cos(π/3+2x)=cos(2(X+π/6))=2cos(x+π/6)*cos(x+π/6)-1=2*25/169-1=
自己算吧
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