x+y=36 2*25x=40y 求这个方程组的解,

x+y=36 2*25x=40y 求这个方程组的解 x+y=36 2*25x=40y 求这个方程组的解, x+y=36 2*25x=40y 求这个方程组的解, 2x+y=1,25x+2y=-40,求x和y? 已知X*X+Y*Y+6X-8Y+25=0 求（Y/X)+(X/Y)-2=? X+Y=36 2×25X=40Y 这个方程组怎么解? 1.已知2x+y=4,求这个整式[(x+y)^2-(x-y)^2-2y(x-1/2 y)]÷4y的值 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) x+x+x+y=52 y+y+y+x=36求x x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 y=2x*arctan(y/x),求y‘’ 已知x-y=3,求[（x+y)(x-y)-(x-y)^2+2y(x-y)]除以的值 已知3x =2y 求x/x+y+y/x-y-y²/x²-y² x+y=36 2*25x=40y 求方程组的解 (x+y)(x+y-10)+25=0,且x-y=3,求x,y (x+y)(x+y-10)+25=0,且x-y=3,求x,y 如果|X|=4 |Y|=2 且|X+Y|=X+Y 求X+Y 已知|x|=2,|y|=3,|x+y|=-(x+y)求x-y