已知tan(π-α)=-1/2,且α为第三象限角,求cos(π/2+α)的值求cos(π/2+α)的值求[2sin(π-α)-3cos(π+α)]/[3cos(π-α)+4sin(-α)]

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/28 22:13:10
已知tan(π-α)=-1/2,且α为第三象限角,求cos(π/2+α)的值求cos(π/2+α)的值求[2sin(π-α)-3cos(π+α)]/[3cos(π-α)+4sin(-α)]已知tan(

已知tan(π-α)=-1/2,且α为第三象限角,求cos(π/2+α)的值求cos(π/2+α)的值求[2sin(π-α)-3cos(π+α)]/[3cos(π-α)+4sin(-α)]
已知tan(π-α)=-1/2,且α为第三象限角,求cos(π/2+α)的值
求cos(π/2+α)的值
求[2sin(π-α)-3cos(π+α)]/[3cos(π-α)+4sin(-α)]

已知tan(π-α)=-1/2,且α为第三象限角,求cos(π/2+α)的值求cos(π/2+α)的值求[2sin(π-α)-3cos(π+α)]/[3cos(π-α)+4sin(-α)]
tanα=1/2 sinα/(1-根号下sinα平方)=1/2 两边平方且sin

愤怒炽热的