3/4x+4/3y=1/6,4/3x+3/4y=1/4
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3/4x+4/3y=1/6,4/3x+3/4y=1/43/4x+4/3y=1/6,4/3x+3/4y=1/43/4x+4/3y=1/6,4/3x+3/4y=1/4x和y都是在分母上的么?对第一个式子乘
3/4x+4/3y=1/6,4/3x+3/4y=1/4
3/4x+4/3y=1/6,4/3x+3/4y=1/4
3/4x+4/3y=1/6,4/3x+3/4y=1/4
x和y都是在分母上的么?
对第一个式子乘以4/3,
得到1/x + 16/9y=2/9
第二个式子乘以3/4,
得到1/x +9/16y=3/16,
减去1/x + 16/9y=2/9
求出y=35
那么x=35/6
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
(-x+6):(x-y);(4x+y)=3;14:1,求x+y的值.
求值域 1,y=(x+2)/(x*x+3x+6) 2,y=3x/(x*x+4)
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
{3(x+y)+3(y+x)=1,3(x+y)+4(y-x)=-1
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
解二元一次方程组:3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
(y-x)+x(x-y)^3-(y-x)^4 因式分解
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²