但是是英文的,希望有人可以帮忙!Two in-phase speakers are 2.80 m apart and emit an unknown single frequency of sound in all directions.At a point 2.00 m away from one speaker on the line AB between the two speakers a sound detector record
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但是是英文的,希望有人可以帮忙!Two in-phase speakers are 2.80 m apart and emit an unknown single frequency of sound in all directions.At a point 2.00 m away from one speaker on the line AB between the two speakers a sound detector record
但是是英文的,希望有人可以帮忙!
Two in-phase speakers are 2.80 m apart and emit an unknown single frequency of sound in all directions.At a point 2.00 m away from one speaker on the line AB between the two speakers a sound detector records a sound intensity maximum.The detector is then moved perpendicularly away from the line AB.The first time the sound intensity is again measured to be a maximum occurs at y= 1.82 away from the line AB.
What is the frequency of the sound emitted by the speakers?(NOTE:The path difference decreases as the detector moves away from the line AB; therefore you can't assume that the path difference initially is one wavelength.You must leave n as a variable and algebraically eliminate it.)
但是是英文的,希望有人可以帮忙!Two in-phase speakers are 2.80 m apart and emit an unknown single frequency of sound in all directions.At a point 2.00 m away from one speaker on the line AB between the two speakers a sound detector record
两个同相的扬声器相距2.80m,分别向四周各个方向发射未知单频率的声波.在扬声器之间AB的连线上,距一个扬声器2.00m处,一个声波检测者观测到了声音强度的极大值.然后检测者垂直于AB连线移动,在距AB连线的垂直距离为y=1.82m处第一次再次（真别扭,理解就好）测得声音强度的极大值.
问扬声器发射的波的频率是多少?（提示不翻译了,大意是在距A2.00m处的极大不能把路程差取为1个波长,应该是n个波长）
记第一次极大处为C点,垂线上再次极大处为D点.
由提示,显然有nλ=AC-BC
又有（n-1）λ=AD-BD
由勾股定理可求出AD,BD
算出n,λ.根据λf=v,v=340m/s算出频率f.
（楼主数据没错吗?我算了一下,n竟然不是整数.反正已经翻译了,你自己算算吧.）
原子的假设的
也许就是因为原子的假设，使物理学有现在这样辉煌的成果。 原子可看作地球一原子是构成元素的最小单元，是物质结构的一个层次．原子一词来自希腊文，“