化简cos(π/6+x)+cos(π/6-x)

化简cos(π/6+x)+cos(π/6-x) cos(x)*cos(π/6-x) 接下来怎么化简 化简sin2x-cos(2x+π/6) cos(2x-π/3）+cos（2x+π/6）化简 已知f(x)=sin(π/6-x)^2-cos(π/4+x)^2+cos(π/6)cos(π/6-2x)化简f(x) 化简cos(π/6a)+cos(π／6-a)= cos(-x-2π) 和cos(π-x) 化简 化简：cos(π/4-x)乘cos(π/4+x) cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简 已知cos(x-π/6)=-根号三分之三 则cos(x)+cos(x-π/3)的值是 （1）化简:根号2sin(π/4-x)+根号6cos(π/4-x)（2）sin(67°-x)cos(x-22°)+cos(67°-x)cos(112°-x)的值为 化简:根号2sin(π/4-x)+根号6cos(π/4-x)(2)sin(67°-x)cos(x-22°)+cos(67°-x)cos(112°-x)的值为 函数f(x)=cos(x+2/π)cos(x+π/6)的最小正周期 2sinxcosx-cos(2x-π/6)化简 化简:cos((6n+1)/6*π+x)+cos((6n-1)/6*π-x)(n属于z) 为什么cos(2x-π/3)-sin(5π/6) =cos(2x-π/3)? cos(x-π/6)=m,则cosx+cos(x-π/3)=_______ cos(2x-1/3π)+cos(2x+6/π)怎样化成一角一函数