(x^3+y^3+z^3-3xyz)怎么因式分解?急
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(x^3+y^3+z^3-3xyz)怎么因式分解?急(x^3+y^3+z^3-3xyz)怎么因式分解?急(x^3+y^3+z^3-3xyz)怎么因式分解?急x³+y³+z³
(x^3+y^3+z^3-3xyz)怎么因式分解?急
(x^3+y^3+z^3-3xyz)怎么因式分解?
急
(x^3+y^3+z^3-3xyz)怎么因式分解?急
x³+y³+z³-3xyz
=x³+3x²y+3xy²+y³+z³-3x²y-3xy²-3xyz
=(x+y)³+z³-3xy(x+y+z)
=(x+y+z)(x²+2xy+y²-xz-yz-3xy)
=(x+y+z)(x²+y²+z²-xy-yz-xz)
x+y+z-3xyz怎么因式分解?
3x^2y-{xyz-(2xyz-x^2z)-4x^2z+[3x^2y-(4xyz-5x^z-3xyz)]}化简
2x+3y+4z,xyz
24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
24xy^2*z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
xyz-【2xy-(3xyz-yz)+4xyz】,其中x=2,y=-1/2,z=-1
xyz-【2xy-(3xyz-yz)+4xyz】,其中x=2,y=-1/2,z=-1
(x^3+y^3+z^3-3xyz)怎么因式分解?急
求24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)怎么做!明天要交嗯,七年级数学练习册28页第8题,24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y),
代数式的恒等变形3已知(x+y+-z)/z=(x-y+z)/y=(-x+y+z)/x且xyz不等于0求分式(x+y)(y+z)(z+x)/xyz的值
x²(y+z)+y²(x+z)z²(x+y)-3xyz因式分解
xyz是正实数,求证:x/(y+z)+y/(z+x)+z/(x+y)>=3/2
x^3+x^2y-x^z-xyz分解因式
已知xyz满足|3x-2y+z|+|2x+y+2z|=0(xyz不等于o)求x+y除以z
3x平方y-[2x平方y-(2xyz-x平方z)-4x平方z]-xyz x=-2 y=-3 z=1 怎么化简求值
化简3X^2y-{xyz-(2xyz-9x^2z+4x^2z)+[3x^2y+(4xyz-5x^2z-3xyz)]}等于( )A 2xyz-2x^2z B 6x^2y-4xyz+2x^2zC 6x^2y+2xyz-10x^2z D 8xyz+10x^2z
先化简,再求值:3xyz+2(x²y+y²z-xyz)-xyz+2z²x,其中x=1、y=-1、z=2;