2\(3x^2+4x+7)=1\4 求1\(6x^2+8x-1)
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2\(3x^2+4x+7)=1\4求1\(6x^2+8x-1)2\(3x^2+4x+7)=1\4求1\(6x^2+8x-1)2\(3x^2+4x+7)=1\4求1\(6x^2+8x-1)最后答案=1,
2\(3x^2+4x+7)=1\4 求1\(6x^2+8x-1)
2\(3x^2+4x+7)=1\4 求1\(6x^2+8x-1)
2\(3x^2+4x+7)=1\4 求1\(6x^2+8x-1)
最后答案=1,因为2\(3x^2+4x+7)=2/8,3x^2+4x+7=8 3x^2+4x-1=0 6x^2+8x-2=0
故 6x^2+8x-1=1
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