(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1-10%-18%)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/16 15:34:49
(1-25%)÷(1+1/3)(80%-2/5÷2)×75%7.2÷(1(1-25%)÷(1+1/3)(80%-2/5÷2)×75%7.2÷(1-10%-18%)(1-25%)÷(1+1/3)(80%
(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1-10%-18%)
(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1
(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1-10%-18%)
(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1-10%-18%)
(1-25%)÷(1+1/3)
=0.75÷4/3
= 0.5625 (80%-2/5÷2)×75%
=(80%-1/5)x75%
=60%x75%
=0.45
7.2÷(1-10%-18%)
=7.2÷72%
=10
这是一道题还是三道题啊
收起
(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1(1-25%)÷(1+1/3) (80%-2/5÷2)×75% 7.2÷(1-10%-18%)
80÷(1-2/3+1/5)=
80÷1.5x-80÷(80-x)=1/3
-3²+(-3分之1)²×(-3)³÷(-1)^25
(1-1÷2)(1-1÷3)(1-1÷4)...(1-1÷n)
-1平方-36÷︱-(3)平方︱÷4/25×25/4
(1)(1000×70%-100×70%)×1/9(2)80%×3/4-20%×0.5(3)10÷25+1/2×3/10(4)(7/12-1/4)÷1/2+1/3(5)6/11÷(40%×7/11)+6/7(6)3/5×6/7+20%×3/7没有简算就说没有简算
(2/71-1/69)×23+25÷71+15又1/3÷23
[51 -(18 3/4 - 1÷ 8/15 )× 1 23/25]÷ 0.62
(1) (-5.2)÷3又25分之3过程(2) -2.25÷1又8分之1×(-8)(3) (-1)÷(-4又3分之2)÷(-3又2分之1)
(1)(-25)÷(-5)=(2)0÷(-20)= (3)(-3)×三分之一÷(负三分之一)÷3=
1:1/5×[1/3÷(1/2+5/6)] 2:1-(1/6×2/5)÷7/9 3:12÷(1-31:1/5×[1/3÷(1/2+5/6)]2:1-(1/6×2/5)÷7/93:12÷(1-3/7)4:4/5×2/3-1/6÷1/25:(1/2+1/3)÷(1-3/8)6:[(1-3/5)×2/3]÷4
(-5.2)÷3又25分之3 -2.25÷1又8分之1×(-8(-5.2)÷3又25分之3 -2.25÷1又8分之1×(-8 ) (-1)÷(-4又3分之2)÷(-3又2分之1 )26×1又3分之2÷(-3分之2) 计算
[1-(1/12+1/15)×2]÷(3/10+9/25)
就一题 根据算式补充条件.小兵两天看完一本童话书,第一天看了80页,( ).第二条看了多少页?(1)80×(1+1/3) (2)80×(1-1/3)(3)80÷(1+1/3) (4)80÷(1-1/3)1.( )2.( )3.( )4.( )
(80%+25%)÷(7÷3)+0.7=?
-3²×1.2²÷(-0.3)³+(0.2)²×(-3)³÷(-1)25次方
(32*1/4+17)÷5/12 (25+3/4)÷1/4+1/4 18/25×9/16+7/25*9/16+9/16