函数f(x)=2sin(2x+π/6)-1的值域怎么求

函数f(x)=sin(2x+π/6),g(x)=cos(x+φ),|φ| 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+a) -π 设函数f(x)=sin(2x+ φ)(-π 函数f(x)=sin(2x+&）(-π 函数f(x)=sin(2x+t) (-π 函数f(x)=sin(2x+a）(-π 设函数f(x)=sin(2x+φ)(-π