已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5

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已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5设g

已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5
已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5<=f(x)<=1.
设g(x)=f(x+π/2)且lg g(x)>0,求g(x)的单调区间.

已知函数a>0,函数f(x)=-2asin(2x+π/6)+2a+b,当x∈[0,π/2]时,-5
当x∈[0,π/2]时,-1/2