设log(2)(3)=a,log(3)(7)=b,以a,b表示log(21)(56)

设log(2)(3)=a,log(3)(7)=b,以a,b表示log(21)(56) 设log（a）2/3下面 log(2)3=a,则log(6)4=（ log a 2/3 log a(2/3) 对数函数题 log a - log b = 3 log (c/2) 求 a = ______________ 设a>b>1,log(a)b+log(b)a=10/3,则log(a)b-log(b)a= 设a=1/log(4)3+1/log(7)3,求证a属于(3,4) 设a=log(1/3)1/2 b=log(1/3)2/3 c=log(3)4/3 则abc的大小 关系是? 1、若lg2=a,lg3=b,则lg√15=?（用a、b表达）2、若log(15)(5)=m,则log(15)(3)=(用m表示)3、log(2)(3)*log(3)(4)*log(4)(5)*log(5)(6)*log(6)(7)*log(7)(8）=?4、设log(3)(2)=log(2)(3^x),x=?这个对数函数我学的很不好,所以希望过 log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃.... 求等式log(2)3*log(3)4*log（4)5*log(5)6*log(6)7*log(7)m=log(3)9时m的值? 已知log（14）7=a log(14)5=b 用ab表示log(35)70=log(3)4*log(4)8*log(8)m=log(4)2 求m 证明对数运算法则（1）log(a)(MN)=log(a)(M)+log(a)(N); 　　（2）log(a)(M/N)=log(a)(M)-log(a)(N);（1）log(a)(MN)=log(a)(M)+log(a)(N); 　　（2）log(a)(M/N)=log(a)(M)-log(a)(N); 　　（3）log(a)(M^n)=nlog(a)(M) （n∈R） 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 设y=1+log a(x+3),求反函数 设log√3 2=1-a/a则log12 3=设log√3 2=1-a/a则log12 3= 第八题