x1=m,x2=n是方程X2+5X+80=0的根求(M2+5M+72)(N2+5N-26)的值 “方程”俩字后面的2都是平方
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x1=m,x2=n是方程X2+5X+80=0的根求(M2+5M+72)(N2+5N-26)的值 “方程”俩字后面的2都是平方
x1=m,x2=n是方程X2+5X+80=0的根求(M2+5M+72)(N2+5N-26)的值
“方程”俩字后面的2都是平方
x1=m,x2=n是方程X2+5X+80=0的根求(M2+5M+72)(N2+5N-26)的值 “方程”俩字后面的2都是平方
把x1=m带入方程得:m^2+5m+80=0
所以m^2+5m+72=-8
把x2=n带入方程得:n^2+5n+80=0
所以n^2+5n-26=-106
所以(m^2+5m+72)(n^2+5n-26)=-8*(-106)=848
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