sinA+cosA=1/2,则sin(A+π/4)=?
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sinA+cosA=1/2,则sin(A+π/4)=?sinA+cosA=1/2,则sin(A+π/4)=?sinA+cosA=1/2,则sin(A+π/4)=?原式=sinAcosπ/4+cosAs
sinA+cosA=1/2,则sin(A+π/4)=?
sinA+cosA=1/2,则sin(A+π/4)=?
sinA+cosA=1/2,则sin(A+π/4)=?
原式=sinAcosπ/4+cosAsinπ/4
=√2/2*(sinA+cosA)
=√2/4
sin(A+45°)=sinAcos45°+cosAsin45°=(sinA+cosA)*(√2/2)=√2/4
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