已知:Ia+1I+Iab+2I=0,求1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2008)(b+2008)的值

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/08 18:00:27
已知:Ia+1I+Iab+2I=0,求1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2008)(b+2008)的值已知:Ia+1I+Iab+2I=0,求1/(a+1)(b+1)+1

已知:Ia+1I+Iab+2I=0,求1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2008)(b+2008)的值
已知:Ia+1I+Iab+2I=0,求1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2008)(b+2008)的值

已知:Ia+1I+Iab+2I=0,求1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2008)(b+2008)的值
从|a+1|+|ab+2|=0可以知道a=-1,b=2
后面因式第一项分母为0无意义,如果你题目没写错的话.