3sin^2a+2sin^2b=1,3(sina+cosa)^2-2(sinb+cosb)^2=1.则cos2(a+b)=cos2(a+b)=cos(2a+2b)=cos2a*sin2a+cos2b*sin2b=?
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3sin^2a+2sin^2b=1,3(sina+cosa)^2-2(sinb+cosb)^2=1.则cos2(a+b)=cos2(a+b)=cos(2a+2b)=cos2a*sin2a+cos2b*
3sin^2a+2sin^2b=1,3(sina+cosa)^2-2(sinb+cosb)^2=1.则cos2(a+b)=cos2(a+b)=cos(2a+2b)=cos2a*sin2a+cos2b*sin2b=?
3sin^2a+2sin^2b=1,3(sina+cosa)^2-2(sinb+cosb)^2=1.则cos2(a+b)=
cos2(a+b)=cos(2a+2b)=cos2a*sin2a+cos2b*sin2b=?
3sin^2a+2sin^2b=1,3(sina+cosa)^2-2(sinb+cosb)^2=1.则cos2(a+b)=cos2(a+b)=cos(2a+2b)=cos2a*sin2a+cos2b*sin2b=?
解
3sin^2a+2sin^2b=1等价于
3(1-cos2a)+2(1-cos2b)=1
3cos2a+2cos2b=4
3(sina+cosa)^2-2(sinb+cosb)^2=1等价于
3(1+sin2a)-2(1+sin2b)=1
3sin2a-2sin2b=-4
这是哪来的,说清楚一点。才好为你回答
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