sin阝=1/3,sin(a+阝)=1,求sin(2a+3阝)
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sin阝=1/3,sin(a+阝)=1,求sin(2a+3阝)sin阝=1/3,sin(a+阝)=1,求sin(2a+3阝)sin阝=1/3,sin(a+阝)=1,求sin(2a+3阝)sin
sin阝=1/3,sin(a+阝)=1,求sin(2a+3阝)
sin阝=1/3,sin(a+阝)=1,求sin(2a+3阝)
sin阝=1/3,sin(a+阝)=1,求sin(2a+3阝)
sin²(a+阝)+cos²(a+阝)=1
cos²(a+阝)=1-sin²(a+阝)=1-1=0
cos(a+阝)=0
∴sin2(a+阝)=2sin(a+阝)cos(a+阝)=0
∴cos2(a+阝)=±1
sin(2a+3阝)
=sin[2(a+阝)+阝]
=sin2(a+阝)cos阝+cos2(a+阝)sin阝
=0+1/3cos2(a+阝)
=±1/3
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sin阝=1/3,sin(a+阝)=1,求sin(2a+3阝)
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