(1+sin (2B))/(cos^2 (B)-sin^2 (B))=-3 #求tan B 角B是三角形一内角

证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1 sin(a-b)*cos a-cos(a-b)*sin a=1/5,则cos 2b的值是 由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证：1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a) Cos(a+b)*cos(a-b)=1/5 求cos ^2-sin^2 求证:sin^2/(sin-cos) - (sin+cos)/(tan^2 -1) =sin+cos 化简cos(a+b)cos(a-b)+sin^2b SIN^2 A+SIN^2 B-SIN^2 A*SIN^2 B+COS^2 A*COS^2 b等于 1有谁会啊 教教 求证.(2),sin平方a+sin平方b-sin平方a*sin平方b+cos平方a*cos平方b=1 1/2(cos(2B)-cos(2A))=sin(B)sin(A+B)是怎么导出的 已知sin(a+b)sin(a-b)=-1/3,求cos^2a-cos^2b的值 已知sin^4a/cos^2b+cos^4a/sin^2b=1,求证:sin^4 b/cos^2 a+cos^4b/sin^2a=1 已知(cos^4a)/cos^2b+(sin^4a)/sin^2b=1求证(cos^4b)/cos^2a+(sin^4b)/sin^2a=1 若sin^4a/sin^2b+cos^4a/cos^2b=1,证明sin^4b/sin^2a+cos^4b/cos^2a=1.(不用向量怎么证?) 已知cos(a+b)cos(a-b)=1/3,则cos^2a-sin^2b的值是? cos(a+B)×cos(a-B)=1/3,求cos^2(a)-sin^2(B)的值 化简：1+sinθ+cosθ+2sinθcosθ /1+sinθ+cosθ 化简sin^2a+sin^2b-sin^2a*sin^2b+cos^2a*cos^2b sin^2a+sin^2b-sin^2a * sin^2b+cos^2a * cos^2b 化简