Cos(a+b)*cos(a-b)=1/5 求cos ^2-sin^2

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Cos(a+b)*cos(a-b)=1/5求cos^2-sin^2Cos(a+b)*cos(a-b)=1/5求cos^2-sin^2Cos(a+b)*cos(a-b)=1/5求cos^2-sin^2原

Cos(a+b)*cos(a-b)=1/5 求cos ^2-sin^2
Cos(a+b)*cos(a-b)=1/5 求cos ^2-sin^2

Cos(a+b)*cos(a-b)=1/5 求cos ^2-sin^2
原题是这样子吧:
cos(a+b)cos(a-b)=1/5,则(cosa)^2-(sinb)^2=?
cos(a+b)cos(a-b)
=(cosacosb-sinasinb)(cosacosb+sinasinb)
=(cosacosb)^2-(sinasinb)^2
=cosa^2[1-(sinab)^2]-sinb^2[1-(cosa)^2]
=(cosa)^2-(sinb)^2
=1/5