x^3+7x^2-11x+4除以x+5 这道题应该是要化简.是不是要把分母因式分解?可是要怎么分解呢?

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 6除以x+1=x+5除以3-2x=4搞错了，应该 是6除以x+1=x+5除以x（x+1) (5x-2除以x-1)+1=4x+5除以3x-3无 1除以5-x+2除以4-x+3除以3-x=-3 3（x-根号2）=5x+1 3x除以4-1=5x-7除以6 3x-y+x=3 4【X-y-1】=3【1-y】-1 5x-4y+4x=3 2x+y-3x=11 【 x除以2 】-【y 除以3】 =2 2x+7y-3x=19 x+y+x=12 3x+2y-x=18 先化简,再求值:x^3+2x^2+x/x^2+2x-8除以（x/x-2 × x+1/x+4),其中x=负5/4 [(x+3分之x+2)-(x+2分之x+1)+(x+5分之x+4)-(x+4分之x+3)]除以[(x平方+8x+15)分之(x平方+7x+13)] xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 2X除以7加4分之1X的和除以5X除以7加3X除以4等于? 通分x+4除以x²+4x与x-5除以x(x-5)-2(x-5) x除以2 大于 x除以3 求值：(x/x^2-1)除以(x^2+4x+3)/(x^2+2x+1) [x(-4x+3)+(x+2)(x-2)x]除以(-x) 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 2x-6/x^2-4x+4除以12-4x/x^2+5X-6除以x^2+5x+6/x^2-5x-6 X+1)除以（x+2）加上（x+6）除以（x+7）等于（x+2）除以（x+3）加上（x+5）除以（x+6）求x