lim(2x^3-3x^2+1)/[(x-1)(4x^n+7)] 则n=lim趋向于无穷大
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lim(2x^3-3x^2+1)/[(x-1)(4x^n+7)]则n=lim趋向于无穷大lim(2x^3-3x^2+1)/[(x-1)(4x^n+7)]则n=lim趋向于无穷大lim(2x^3-3x^
lim(2x^3-3x^2+1)/[(x-1)(4x^n+7)] 则n=lim趋向于无穷大
lim(2x^3-3x^2+1)/[(x-1)(4x^n+7)] 则n=
lim趋向于无穷大
lim(2x^3-3x^2+1)/[(x-1)(4x^n+7)] 则n=lim趋向于无穷大
如果是x→∞,
如果整个极限的值是不为0的有限值,
因为分子的最高次幂是3,
则分母的最高次幂也应该是3
1+n=3
n=2
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