1+2···+99
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1+2···+991+2···+991+2···+99首项加末项=100,一共有49对,外加剩余的50,所以1+2···+99=100*49+50=49504950100x(99/2)5000这个要用
1+2···+99
1+2···+99
1+2···+99
首项加末项=100,一共有49对,外加剩余的50,所以1+2···+99=100*49+50=4950
4950
100x(99/2)
5000
这个要用等差数列求和公式:首项加末项的和乘公差除以二
100*49+50
1+99=100
2+98=100
3+97=100
........................
.......................
99+1=100
将这99个式子相加得:
2(1+2+3+...+99)=100*99
(1+2+3+...+99)=100*99/2=4950
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