1+2···+99

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1+2···+991+2···+991+2···+99首项加末项=100,一共有49对,外加剩余的50,所以1+2···+99=100*49+50=49504950100x(99/2)5000这个要用

1+2···+99
1+2···+99

1+2···+99
首项加末项=100,一共有49对,外加剩余的50,所以1+2···+99=100*49+50=4950

4950

100x(99/2)

5000

这个要用等差数列求和公式:首项加末项的和乘公差除以二

100*49+50

1+99=100
2+98=100
3+97=100
........................
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99+1=100
将这99个式子相加得:
2(1+2+3+...+99)=100*99
(1+2+3+...+99)=100*99/2=4950

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