lim(x→∞)[(X^2+2x+5)/(4x^2-x+1) =(1+2/x+5/x^2)/(4-1/x+1/x^2)=(1+0+0)/(4+0+0)=1/4
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 12:53:34
lim(x→∞)[(X^2+2x+5)/(4x^2-x+1)=(1+2/x+5/x^2)/(4-1/x+1/x^2)=(1+0+0)/(4+0+0)=1/4lim(x→∞)[(X^2+2x+5)/(4
lim(x→∞)[(X^2+2x+5)/(4x^2-x+1) =(1+2/x+5/x^2)/(4-1/x+1/x^2)=(1+0+0)/(4+0+0)=1/4
lim(x→∞)[(X^2+2x+5)/(4x^2-x+1) =(1+2/x+5/x^2)/(4-1/x+1/x^2)=(1+0+0)/(4+0+0)=1/4
lim(x→∞)[(X^2+2x+5)/(4x^2-x+1) =(1+2/x+5/x^2)/(4-1/x+1/x^2)=(1+0+0)/(4+0+0)=1/4
对了!
lim xsin(2/x) x→∞
Lim [x^2/(x^2-1)]^x (x→∞)
lim(1+x/x)2x (x→∞)
lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) =
1.lim x->∞ (2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 (e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li
lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4
lim x→∞ (x+sin 2x)/2
lim(x→∞)(1-2/x)^2x
x/2-1lim(1-2/x)x→∞
lim x→∞(2x+1)/(3x-4)
lim(x→+∞) (2/π arctan X)^X
lim(x→∞)(1-2/x) (x+1)次方
lim x→∞ x-1/x^2
lim x→∞(1-2/x)^x=
lim(x→∞)[1+(1/x)]^x/2
求lim(√x^2+1)-x x→-∞
烦人的数学微积分1、lim(x→0)Sin3x/Sin2x2、lim(x→0)x/3*Sin3x3、lim(x→0)[Xsin(3/x)+(tanx/2x)]4、lim(x→3)Sin(x-3)/(X^2-X-6)5、lim(x→∞)[1+(1/2x)^x6、lim(x→∞)(x+3/x)^x7、lim(x→0)(1-x/2)^1/x+118、求下列函数的间断
lim(x→0) (3x^2-5x+2),