求证:sin a(1+tan a)+cos a(1+1/tan a)=1/sin a+1/cos a
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/11 15:34:07
求证:sina(1+tana)+cosa(1+1/tana)=1/sina+1/cosa求证:sina(1+tana)+cosa(1+1/tana)=1/sina+1/cosa求证:sina(1+ta
求证:sin a(1+tan a)+cos a(1+1/tan a)=1/sin a+1/cos a
求证:sin a(1+tan a)+cos a(1+1/tan a)=1/sin a+1/cos a
求证:sin a(1+tan a)+cos a(1+1/tan a)=1/sin a+1/cos a
sin a(1+tan a)+cos a(1+1/tan a)
=sina+sina*tana+cosa+cosa/tana
=(sina+cos^2(a)/sina)+(cosa+sin^2(a)/cosa)
=(sin^2(a)+cos^2(a))/sina+(cos^2(a)+sin^2(a))/cosa
=1/sin a+1/cos a
求证:(tan a*sin a)/(tan a-sin a)=(tan a+sin a)/(tan a*sin a)
求证:sin a(1+tan a)+cos a(1+1/tan a)=1/sin a+1/cos a
求证 cos^2 a-sin^2 a/1-2sin acos a =1+tan a/1-tan a
求证:tan a/2=(1-cos)/sin a=sin a/(cos a+1)
已知sin(a+β)=1,求证;tan(2a+3β)-tanβ=0
求证恒等式:(tan a+sec a-1)/(tan a -sec a+1)=(1+sin a)/cos a
求证tan^2asin^2a=tan^2a-sin^2a求证tan^2 a 乘 sin^2 a=tan^2 a-sin^2 a
求解 已知 sin(a+b)=1/2 ,sin(a_b)=1/3,求证:tan a=5tan b求解:已知 sin(a+b)=1/2 ,sin(a_b)=1/3,求证:tan a=5tan b
已知tan^2 a=2tan^ B +1,求证sin^2 b=sin^2 a -1
已知tan^2A=2tan^B+1求证sin^2B=2sin^2A-1救急
已知tan^2a=2tan^2b+1,求证:sin^b=2sin^2a-1
已知tan²a=2tan²b+1,求证sin²b=2sin²a-1
已知tan^2A=2tan^B+1,求证sin^2B=2sin^2A-1
已知sin^2B=2sin^2A-1求证tan^2A=2tan^B+1
tan^2a=2tan^2⊙+1求证sin^2⊙=2sin^2a-1
已知tan²a=2tan²B+1,求证sin²B+1=2sin²a
已知tan²a=2tan²B+1,求证sin²+2sin²a-1
已知tan²a=2tan²b+1,求证sin²b+1=2sin²a