y=sin(2x+π/2)+2sinαcosα+1最小正周期是?
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y=sin(2x+π/2)+2sinαcosα+1最小正周期是?y=sin(2x+π/2)+2sinαcosα+1最小正周期是?y=sin(2x+π/2)+2sinαcosα+1最小正周期是?y=si
y=sin(2x+π/2)+2sinαcosα+1最小正周期是?
y=sin(2x+π/2)+2sinαcosα+1最小正周期是?
y=sin(2x+π/2)+2sinαcosα+1最小正周期是?
y=sin(2x+π/2)+2sinxcosx+1
=cos2x+sin2x+1
=√2(√2/2cos2x+√2/2sin2x)+1
=√2sin(2x+π/4)+1
最小正周期T=2π/2=π
π
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