解方程[x/(x-1)]^2+[x/(x+1)]^2=40/9.

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/15 09:11:38
解方程[x/(x-1)]^2+[x/(x+1)]^2=40/9.解方程[x/(x-1)]^2+[x/(x+1)]^2=40/9.解方程[x/(x-1)]^2+[x/(x+1)]^2=40/9.[x/(

解方程[x/(x-1)]^2+[x/(x+1)]^2=40/9.
解方程[x/(x-1)]^2+[x/(x+1)]^2=40/9.

解方程[x/(x-1)]^2+[x/(x+1)]^2=40/9.
[x/(x-1)]^2+[x/(x+1)]^2=40/9
9x^2[(x+1)^2+(x-1)^2]= 40[(x+1)(x-1)]^2
9x^2(x^2+1)= 20(x^4-2x^2+1)
11x^4-49x^2+20=0
(11x^2-5)(x^2-4)=0
x= 2 or -2 or √(5/11) or -√(5/11)