如图,AB=CD,AF=CE,BE⊥AC于E,DF⊥AC于F,求证△ABE≌△CDF

AB=CD,AF=CE,BE⊥AC,DF⊥AC,求证BE=DF 如图,AB=CD,AF=CE,BE⊥AC于E,DF⊥AC于F,试说明△ABE≌△CDF. 如图,AB=CD,AF=CE,BE⊥AC于E,DF⊥AC于F,求证△ABE≌△CDF 如图,AB=CD,BE垂直AC,BF垂直AC,E,F是垂足,DE=BF证明AF=CE AB平行于CD 如图,AB=AC,BD⊥AC,CE⊥AB求证BE=CD 已知AB=CD,AF=CE,BE⊥AC于E,DF⊥AC于F.求证：AB//CD 如图,E,F为AC上两点,AB=CD,BE=DF,AF=CE,那么AB∥CD吗?为什么?（要全过程) 如图 AB=CD DF垂直于AC于F BE垂直于AC于E DF=BE 求AF=CE 如图,AB=CD,DF垂直AC于F ,BE垂直AC于E,DF=BE,求证AF=CE. AB=CD,DF垂直AC,BE垂直AC,DF=BE.求证:AF=CE 如图,在四边形ABCD中,AB=CD,BE=DF,AF⊥AB,CE⊥CD,求证:AB||CD 如图,已知AB‖CD,AB=CD,AF=CE,试说明BE=DF 已知：如图,BE⊥AC,DF⊥AC,垂足分别是点E、F.AF=CE,BE=DF.求证：AB=CD,AB//CD 已知：如图,DE//BC,A是DE上一点,AD=AE,AB=AC 求证：BE=CD 如图,AB=AC,CD⊥AB,BE⊥AC,BE与CD相交于点F；求证：AF平分∠BAC 如图,已知CE⊥AB,DF⊥AB,AC=BD,AF=BE,则CE=DF.请说明理由. 如图,E,F是线段AB上两点,AC//BD,CE⊥AB.DF⊥AB,AF=BE.求证AC=BD 如图,△ABC中,AB=AC,延长BC到D,使CD=BC,CE⊥BD交AD于E,连结BE交AC于F.求证：AF=FC. 如图,AB=CD,BE=DF,AF=CE.说明(1)BE=DF(2)AB//CD,BE//DF.