1/(1x5)+1/(5x9)+1/(9x13)+……+1/(401x405) 找规律计算 要过程 急
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1/(1x5)+1/(5x9)+1/(9x13)+……+1/(401x405)找规律计算要过程急1/(1x5)+1/(5x9)+1/(9x13)+……+1/(401x405)找规律计算要过程急1/(1
1/(1x5)+1/(5x9)+1/(9x13)+……+1/(401x405) 找规律计算 要过程 急
1/(1x5)+1/(5x9)+1/(9x13)+……+1/(401x405) 找规律计算 要过程 急
1/(1x5)+1/(5x9)+1/(9x13)+……+1/(401x405) 找规律计算 要过程 急
答：
1/[n(n+4)]=(1/4)*[1/n-1/(n+4)]
所以：
Sn=1/(1*5)+1/(5*9)+...+1/(401*405)
=(1/4)*(1-1/5+1/5-1/9+...+1/401-1/405)
=(1/4)(1-1/405)
=101/405
1/1x5+1/5x9+.+1/2005x2009
1/1x3+1/3x5+1/5x7+1/7x9+1/9x11=?
1/1x3+1/3x5+1/5x7+1/7x9+1/9x11=?
1/1X5+1/5X9+1/9X13+.+1/2005X2009
1/1x5+1/5x9+1/9x13+……1/33x37
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