5/6x1/13+5/9x2/13+5/18x3/13用简便方法做

求线性方程组 2 x1+3 x2+x3=4;x1-2 x2+4 x3=-5;3 x1+8 x2-2 x3=13;4 x1-x2+9 x3=-6的全部解 用初等行变换来解下列线性方程组（1）2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6(2) x1-2x2+x3+x4=1 x1-2x2+x3-x4=-1 x1-2x2+x3-5x4=5(3) x1-x2+x3-x4=1 x1-x2-x3+x4=0 x1-x2-2x3+2x4=-1/2 Mathematica 如何对多项式取模化简?如何对多项式取模化简?例如：输入：s1={Mod[15 x1+17 x2+13 x3,7],Mod[21 x1+23 x2+14 x3,8],Mod[11 x1+19 x2+28,9]}输出：s2 ={x1+3 x2+6 x3,5 x1+7 x2+6 x3,2 x1+x2+1} 求下列非齐次线性方程组的解x1+x2-3x3-x4=13x1-x2-3x3+4x4=4x1+5x2-9x3-8x4=0我已经算到x1+x2-3x3-x4=1-4x2+6x3+7x4=1该怎么分别用x1 x2 x3 x4来表示呢? maxZ= 5x1 +8x2x1 + x2 ≤6?5x1 +9 x2 ≤45x1,x2 ≥0 x1,x2取整数 ｛2X1-X2+3X3=33X1+X2-5X3=04X1-X2+X3=3X1+3X2-13X3=-6{X1-2X2+3X3-4X4=4X2-X3+X4=-3X1+3X2-3X4=1-7X2+3X3+X4=-3 克莱姆法则解方程组x1+x2+2x3+3x4=4X1+x2+x4=43x1+x2+5x3+10x4=124x1+5x2+9x3+13x4=18 线性方程组求解 2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6 线性方程组求解 2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6用矩阵的方法 矩阵线性方程组2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6用消元法怎么计算呢.请需要帮助. matlab解线性方程组请问,13x1=2x1+x2+6x3+4x413x2=4x1+3x2+2x3+3x413x3=2x1+5x2+3x3+3x413x4=5x1+4x2+2x3+3x4这个方程组用matlab应该怎样求解x1 x2 x3 x4 麻烦告之下代码, 题是 求3个equation的值 x1 x2 x3 为3个变量 但是中间有一步没看懂2*x1+4*x2-3*x3＝1x1+x2+2*x3 =93*x1+6*x2-5*x3=0Swapping the first and second equation,we have x1+x2+2*x3 =92*x1+4*x2-3*x3＝13*x1+6*x2-5*x3=0 Next,we subtract 2 lots of 5/6x1/13+5/9x2/13+5/18x3/13用简便方法做 5/6X1/13+5/9X2/13+5/18X6/13大神们帮帮忙 解线性方程组{x1+2x2+x3=10,2x1+5x2+3x3=20,x1+x2+3x3=13} 求解下列非齐次线性方程组!x1-2x2+3x3-x4=13x1-x2+5x3-3x4=22x1+x2+2x3-2x4=3 求解线性方程组 X1+X2+X3=6 2X1+3X2+X3=11 X1-X2+2X3=5 解非齐次线性方程组：2X1-4X2+5X3+3X4=7 3X1-6X2+4X3+2X4=7 4X1-8X2+17X3+11X4=21 X1-2X2+13X3+9X4=14