(1)化简y=COS^4X-sin^4X+1 我知道这道题最后是2cos2x+1 还可以化简吗?(2)y=5/4 sin2x-5/2cos²x+6 急(1)化简y=COS^4X-sin^4X+1 我知道这道题最后是2cos2x+1 还可以化简吗?(2)y=5/4 sin2x-5/2cos²x+6

化简y=sin^4x-cos^4x, y=2sin(x-π/4)cos(x+π/4)+1化简 y=√2sin(2x+π／4)-1/2cos²x 化简~急用~ y=sin^4x+cos^4x的值域 化简sin (x+y)sin x +cos (x+y)cos x= 化简 1-sin^4x-cos^4x/1-sin^6x-cos^6x 化简(1-cos^4x-sin^4x)/(1-cos^6x-sin^6x) 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x (1-cos^4X-sin^4x)∕(1-cos^6x-sin^6x)=化简(急) 函数y=cos^4x-sin^4x的最小正周期y=(cos^2x+sin^2x)(cos^2x-sin^2x)为什么等于cos^2x-sin^2x=cos2x谢谢 化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x) 函数y=sin(x)cos(x+ π/4)+cos(x)sin(x+π/4)的最小正周期是 y=4√2sin x cos x+cos 2x 的值域是 y=sin^2x-3sinxcosx+4cos^2x是否等于y=sin^2x+cos^2x+3cos^2x-3/2*sin2x?y=sin^2x-3sinxcosx+4cos^2xy=sin^2x+cos^2x+3cos^2x-3/2*sin2x=1+3cos^2x-3/2*sin2x=1+3（1-sin^2x）-3/2*sin2x=-3sin^2x-3/2*sin2x+4 y=(sin(x)-1)/(cos(x)+(cos(x))/(sin(x)+1)的奇偶性 求函数y=sin^4 x-cos^4x 最小正周期?化简：sin^2x-cos^2x=1-2cos^2x=- cos2x .T=2π//2=π 6-4x-x^2=5/|sin(y/x)cos(y/x)|的解