(sinπ/12)-(sin5π/12)+(2sinπ/8)(sin3π/8)
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(sinπ/12)-(sin5π/12)+(2sinπ/8)(sin3π/8)(sinπ/12)-(sin5π/12)+(2sinπ/8)(sin3π/8)(sinπ/12)-(sin5π/12)+(
(sinπ/12)-(sin5π/12)+(2sinπ/8)(sin3π/8)
(sinπ/12)-(sin5π/12)+(2sinπ/8)(sin3π/8)
(sinπ/12)-(sin5π/12)+(2sinπ/8)(sin3π/8)
(2sinπ/8)(sin3π/8)=2sinπ/8cosπ/8=sinπ/4=（√2）/2
(sinπ/12)-(sin5π/12)=sin（π/ 4-π/ 6）-sin（π/ 4+π/ 6）=-2cos(π/4)sin(π/6)=-2*[(√2)/2]*1/2
=-(√2)/2
原式=-(√2)/2+(√2)/2=0
计算：sinπ／12 sin5π／12
(sin5π/12-sinπ/12)(sin5π/12+sinπ/12)的值 急!
(sinπ/12)-(sin5π/12)+(2sinπ/8)(sin3π/8)
sinπ/12-sin5π/12+2sinπ/8sin3π/8
(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?
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