(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
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(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)(sin5π/12+cos5π/12)(sinπ/12-
(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
=[sin(π/2-π/12)+cos(π/2-π/12)](sinπ/12-cosπ/12)
=(cosπ/12+sinπ/12)(sinπ/12-cosπ/12)
=sin²π/12-cos²π/12
=-(cos²π/12-sin²π/12)
=-cosπ/6
=-√3/2
cos5π/12-根3sin5π/12过程
(sina5π/12+cos5π/12)(sin5π/12-cos5π/12)
(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?
cos5π/12-tanπ/3sin5π/12的值是
sin5/12π×cos5/12π怎么算?请给出详细过程 谢谢高手了..
sin5/3π= ,cos5/3π
sin5π和cos5π等于多少
（1）根号2cos3x+根号6sin3x； （2）cos5π/12-根号3sin5π/12
cos5/6π=?sin5/6π=?
sin4π+cos3/2π+tan3π-sin5/2π+cos5π,帮算下求下化简过程
计算：sinπ／12 sin5π／12
已知sin(α+β)=3/5,sinβ=1/2,α+β,β均为锐角,求sinα的值.已知sin(α+β)=3/5,cos（α-β）=1/3,α+β,α-β均为锐角,求sin2α、cos2β.求[（sin5π/12）+（cos5π/12）]·[（sin5π/12）-（cos5π/12）]的值.求1+2cos²θ-cos2
sinπ/12cos5π/12等于
求cos5π/12sinπ/12
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