sin5/12π×cos5/12π怎么算?请给出详细过程 谢谢高手了..

sin5/12π×cos5/12π怎么算?请给出详细过程 谢谢高手了.. cos5π/12-根3sin5π/12过程 (sina5π/12+cos5π/12)(sin5π/12-cos5π/12) (sin5π/12+cos5π/12)(sinπ/12-cosπ/12) (sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=? cos5π/12-tanπ/3sin5π/12的值是 sin5/3π= ,cos5/3π sin5π和cos5π等于多少 （1）根号2cos3x+根号6sin3x； （2）cos5π/12-根号3sin5π/12 cos5/6π=?sin5/6π=? sin5/12π*cosπ/12 怎么算 cos5π/12=sinπ/12 怎么算的? sin4π+cos3/2π+tan3π-sin5/2π+cos5π,帮算下求下化简过程 计算：sinπ／12 sin5π／12 已知sin(α+β)=3/5,sinβ=1/2,α+β,β均为锐角,求sinα的值.已知sin(α+β)=3/5,cos（α-β）=1/3,α+β,α-β均为锐角,求sin2α、cos2β.求[（sin5π/12）+（cos5π/12）]·[（sin5π/12）-（cos5π/12）]的值.求1+2cos²θ-cos2 sinπ/12cos5π/12等于 求cos5π/12sinπ/12 (sin5π/12-sinπ/12)(sin5π/12+sinπ/12)的值 急!