解y+2z=-2;3x+y-4z=1;2x-y+2z=8
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解y+2z=-2;3x+y-4z=1;2x-y+2z=8解y+2z=-2;3x+y-4z=1;2x-y+2z=8解y+2z=-2;3x+y-4z=1;2x-y+2z=8第一个式演变为y=-2-2z,把
解y+2z=-2;3x+y-4z=1;2x-y+2z=8
解y+2z=-2;3x+y-4z=1;2x-y+2z=8
解y+2z=-2;3x+y-4z=1;2x-y+2z=8
第一个式演变为y=-2-2z,把y分别代入第二.三个方程,
得到3x-2-2z-4z=1,
2x-(-2-2z)+2z=8
简化为3x-6z=3
x+2z=3 即x=3-2z
把x=3-2z代入3x-6z=3 3(3-2z)-6z=3 可解出z=0.5
x=3-2*0.5=2
y=-2-2*0.5=-3
最终得x=2,y=-3,z=0.5
x=2,y=-3,z=0.5
=25
x=2,y=-3,z=0.5 没错
matlab解对数方程组[x,y,z]=solve('0.29744*x/(3+0.1*x+y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)))^2','0.79*x/(3+0.1*y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.1*y+z)))^2','1.25*x/(3+0.1*z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.*1y+z)*(3+z)/
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
解三元一次方程组 ①2x-y+z=1 3x+y -2z=2 X+2y-z=3 ②x-4y+z=-3 2x+Y-Z=18 X-Y-Z=7 ③4x+4y+2z=7 6X-4y-z=6 2x-y+z=1
x-z=-4 z-2y=-1 x+y-z=-1 怎么解
解三元一次方程组1、x+y-z=4 2x-y+z=5 x-3y+z=-2 2、y+2z=-2 3x+y-4z=1 2x-y+2z=8 3、x-2y+z=-1 x+y+z=2x+2y+3z=-1
解y+2z=-2;3x+y-4z=1;2x-y+2z=8
{x+y+z=4 {2y+z=0 {3x+2y-4z=-1解方程
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
解x+2y+z=8,2x-y-z=-3,3x+y-2z=-1和x+2y+3z=4,y+z=1,3x+2z=3
x+y+z=6 x+2y+3z=14 y+1=z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
解三元一次方程组:(1)x+2y+3z=11x-y+4z=10x+3y+2z=2(2)x:y=3:5y:z=5:6x+y+2z=40(3)x+y-z=2y+z-x=4z+x-y=6谢谢!
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