3M=6,9的N次方=2,则3的2M-4N+1次方=急

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 02:29:13
3M=6,9的N次方=2,则3的2M-4N+1次方=急3M=6,9的N次方=2,则3的2M-4N+1次方=急3M=6,9的N次方=2,则3的2M-4N+1次方=急3的2M-4N+1次方=36÷4×3=

3M=6,9的N次方=2,则3的2M-4N+1次方=急
3M=6,9的N次方=2,则3的2M-4N+1次方=

3M=6,9的N次方=2,则3的2M-4N+1次方=急
3的2M-4N+1次方=36÷4×3=27
3的M次方=6,9的N次方=2
3的2M-4N+1次方=(3^M)^2÷(9^N)^2×3
=36÷4×3=27

3^M=6,2^N=9
3^2M-4^(N+1)
=6^2-2^(2N+2)
=36-2^2*2^2N
=36-4*9^2
=36-4*81
=-288

因3M=6,9的N次方=2
故M=6/2=3,N=log9(2)=log3^2(2)=(1/2)log3(2)

3的2M-4N+1次方=3^[4*3-4*(1/2)log3(2)+1]
=3^12*3/{3^[4*(1/2)log3(2)]}
=3^13/{3^[2*log3(2)]}
=3^13/{[3^log3(2)]^2}
=3^13/(2^2)
=3^13/4=398580.75