x^3-x^2-4x+4
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x^3-x^2-4x+4x^3-x^2-4x+4x^3-x^2-4x+4x^3-x^2-4x+4=x²(x-1)-4(x-1)=(x-1)(x²-4)=(x-1)(x+2)(x-2
x^3-x^2-4x+4
x^3-x^2-4x+4
x^3-x^2-4x+4
x^3-x^2-4x+4
=x²(x-1)-4(x-1)
=(x-1)(x²-4)
=(x-1)(x+2)(x-2)
如果是分解因式,则结果=(x-2)(x-1)(x+2) ,
如果是解方程 x^3-x^2-4x+4=0 ,则其解是 x1 = -2,x2=1,x3=2 。
x^3-x^2-4x+4
=x^3-4x-x^2+4
=(x^2-4)x-(x^2-4)
=(x^2-4)(x-1)
=(x+2)(x-2)(x-1)
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