(1/3)^[log(1/2)^(x^2-3x+1)](1/2)是底数(x^2-3x+1）是指数

log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解, 1/log（2）x+1/log（3）x+1/log（4）x=1,x=? 试解关于x的不等式log(2)x+4log(3)x+12log(8)x+n·2^(n-1)·log(2^n)x 对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(2)(3)} X {log(3)(4)+log(9)(2)}3.(lg2)^+1g2X 1g5 +1g50 log(X+5)+log(X+2)=1 log 9 X/Y=1/2(log 3 X - log 3 Y) log 9 X/Y=1/4 3log 3 X =2log 3 Y find X and Y 2log^(x^2) = 3{2^(1+log x)} + 16 2log^(x^2) = 3{2^(1+log x)} + 16 log根号2（X-1) log(1/2)^(x^2+2x-3)>log(2)^[1/(3x-1)] 2log底3x+log底3 2=1/2log底3 16 x为什么值 log底数7[log底数3（log底数2X）]=0,那么x^1/2的值是 2log(x)(25)-3log(25)(x)=1怎么解X啊.急 log(9)x+log(x^2)3=1的解为?原方程可可化为log(3 ²)x+log(x)²3=1 ,∴1/2*log(3)X+1/2*log(x)3=1,∴[log(3)x]²-2log(x)3+1=0,即[log(3)x-1]²=0请问这里的[log(3)x]²-2log(x)3+1=0是怎么推出来的,刚学基础不好, 函数y=log(1/2)2x+log(1/3)x的单调区间为 log(1/2) (x+1)>log(1/4) (3x+4)求对数不等式 log(2)(x-1)=log(2)(x2+2x-3)求解!要步骤!谢谢 解[log(x-1)]²+2log(x-1)-3=0 log下标（1/3）=2log下标2x,求x.