解方程x^2y^2-8xy+4x^2+y^2+4=0

解方程x^2y^2-8xy+4x^2+y^2+4=0 解方程xy'=(√x^2-y^2)+y 1.解方程x^2+y^2=4 xy-y^2+4=0 2.3x^2-y^2=8 x^2+xy+y^2=42.3x^2-y^2=8 x^2+xy+y^2=4 1.解方程x^2+y^2=4 xy-y^2+4=0 解方程 x^2y^2+x^2+4xy+y^2+1=0 证明：代数式[(x+y)(x-y)-(x+y)^2-2y(x-y)-2xy]/xy 的值为x,y的值无关 解方程 (x+1)^5/(-1-x)^4=3x+7一定要100%正确阿. 化简：3x^2-[5xy-(x^y-3xy)+4x^2y-8xy] 因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y) X×X-2XY-Y×Y+2X-2Y+2=02X×2X-4XY-2Y×2Y+3X-3Y+4=0X×X+2XY+Y×Y+X+Y-56=0X×X-2XY+Y×Y-X+Y-12=0X×X-3XY+Y×Y=-13X×3X-XY+3Y×3Y=13 两个在一起的方程之间有所联系（要求一步一步写出来） (x+4)(y-1)=xy (x-2)(y+1)=xy 这个方程怎么解啊 方程10x^2-16xy+8y^2+6x-4y+1=0 则x-y等于?10x^2-16xy+8y^2+6x-4y+1=0 则x-y等于? (x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1) 解方程（x+2)²+(x-4)(x+4)=(2x-1)(x+4)已知：x²+xy=12,xy+y²=15,求（x+y)²-(x+y)(x-y)的值 求解方程Y'X^2=XY-Y^2 1.（x^2y-xy^2)除以（x-y) 2.x^2-5x-+6 3.3x^2-8x+4 解方程1,x^2-4x+3 =0 2.2y^2-5y+2=0 化简分式方程:x*x-xy-y*y/x*x-3x-6y+2xy 根号(1-x)^2=x-1 解方程 2x^4=3(3+x)(3-x) 解方程 解方程组：（x+y)^2-6(x+y)+8=0 3x^2-2xy-y^2=8 计算:2xy/(x+y)².(x+y)/4y 1-2/x+y=xy,4y+6x=xy.求xy的解?