α是第三象限角:f(α)=[sin(π-α)cos(2π-α)tan(-α+((3π)/2))]/[cot(-α-π)sin(-π-α])1.化简f(α)2.若cos(α-((3π)/2)π)=1/5 求f(a)3.若α=-1860°,求f(α)

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α是第三象限角:f(α)=[sin(π-α)cos(2π-α)tan(-α+((3π)/2))]/[cot(-α-π)sin(-π-α])1.化简f(α)2.若cos(α-((3π)/2)π)=1/5

α是第三象限角:f(α)=[sin(π-α)cos(2π-α)tan(-α+((3π)/2))]/[cot(-α-π)sin(-π-α])1.化简f(α)2.若cos(α-((3π)/2)π)=1/5 求f(a)3.若α=-1860°,求f(α)
α是第三象限角:f(α)=[sin(π-α)cos(2π-α)tan(-α+((3π)/2))]/[cot(-α-π)sin(-π-α])
1.化简f(α)
2.若cos(α-((3π)/2)π)=1/5 求f(a)
3.若α=-1860°,求f(α)

α是第三象限角:f(α)=[sin(π-α)cos(2π-α)tan(-α+((3π)/2))]/[cot(-α-π)sin(-π-α])1.化简f(α)2.若cos(α-((3π)/2)π)=1/5 求f(a)3.若α=-1860°,求f(α)
(1)f(α)=[sin(π-α)cos(2π-α)tan(-α+((3π)/2))]/[cot(-α-π)sin(-π-α])
=(sinacosacota)/(-cotasina)=-cosa
(2)cos(α-((3π)/2)π)=1/5 即cosa=-1/5,所以f(a)=1/5
(3)α=-1860°=-1800°-60°,所以f(α)=-cos(-60°)=-cos60°=-1/2