已知x/2=y/3=z/4≠0,求(2x+3y-z)/(x-2y+3z)的值.
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已知x/2=y/3=z/4≠0,求(2x+3y-z)/(x-2y+3z)的值.已知x/2=y/3=z/4≠0,求(2x+3y-z)/(x-2y+3z)的值.已知x/2=y/3=z/4≠0,求(2x+3
已知x/2=y/3=z/4≠0,求(2x+3y-z)/(x-2y+3z)的值.
已知x/2=y/3=z/4≠0,求(2x+3y-z)/(x-2y+3z)的值.
已知x/2=y/3=z/4≠0,求(2x+3y-z)/(x-2y+3z)的值.
x/2=y/3=z/4≠0可推出y=3/2x,z=2x
所以2x+3y-z=2x+9/2x-2x=9/2x
x-2y+3z=x-3x+6x=4x
(2x+3y-z)/(x-2y+3z)=9/8(因为不等于0,所以可以把x约分掉)
令x/2=y/3=z/4=k,则x=2k,y=3k,z=4k,那么(2x+3y-z)/(x-2y+3z)=9/8
令a=x/2=y/3=z/4
则x=2a,y=3a,z=4a
所以原式=(4a+9a-4a)/(2a-9a+12a)
=9a/5a
=9/5
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