x+2y+3z=1 2x+3y+z=2 3x+y+2z=3
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x+2y+3z=12x+3y+z=23x+y+2z=3x+2y+3z=12x+3y+z=23x+y+2z=3x+2y+3z=12x+3y+z=23x+y+2z=3末日之剑vc,x+2y+3z=1(1)
x+2y+3z=1 2x+3y+z=2 3x+y+2z=3
x+2y+3z=1 2x+3y+z=2 3x+y+2z=3
x+2y+3z=1 2x+3y+z=2 3x+y+2z=3
末日之剑vc ,
x+2y+3z=1(1)
2x+3y+z=2(2)
3x+y+2z=3(3)
(1)+(2)+(3),得
6x+6y+6z=6
x+y+z=1(4)
(2)-(1),得
x+y-2z=1(5)
(4)-(5)得
3z=0
z=0(6)
(6)代入(4)得
x+y=1(7)
(7)代入(1),得
1+y=1
y=0(8)
(8)代入(7)得
x=1
所以方程组的解是:x=1,y=0,z=0
x=1,y=0,z=0
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