用因式分解法解（2x-5）²-2x+5=0

用因式分解法解（2x-5）²-2x+5=0
用因式分解法解（2x-5）²-2x+5=0

用因式分解法解（2x-5）²-2x+5=0
（2x-5）²-2x+5=0
(2x-5)²-(2x-5)=0
(2x-5)(2x-5-1)=0
2x-5=0或2x-6=0
∴x1=5/2,x2=3

(2x-5)^2-2x+5=0
(2x-5)^2-(2x-5)=0
(2x-5)(2x-5-1)=0
(2x-5)(2x-6)=0
x=5/2或x=3

(2x-5)(2x-5-1)=0
(2x-5)(2x-6)=0
x1=5/2
x2=3

原式等于(2x-5)(2x-5-1)=0 2x-5=0 x=2.5 2x-6=0 x=3

（2x-5）²-2x+5=(2x-5)(2x-5-1)=(2x-5)(2x-6)

(2x-5)^2-(2x-5)=0
(2x-5)(2x-5-1)=0
x1=5/2,x2=3